| 1 | #!/bin/bash |
| 2 | |
| 3 | # Weird case from bash-help mailing list. |
| 4 | # |
| 5 | # "Evaluations of backticks in if statements". It doesn't relate to if |
| 6 | # statements but to $?, since && and || behave the same way. |
| 7 | |
| 8 | # POSIX has a special rule for this. In OSH strict-argv is preferred so it |
| 9 | # becomes a moot point. I think this is an artifact of the |
| 10 | # "stateful"/imperative nature of $? -- it can be "left over" from a prior |
| 11 | # command, and sometimes the prior argv is []. OSH has a more "functional" |
| 12 | # implementation so it doesn't have this weirdness. |
| 13 | |
| 14 | #### If empty command |
| 15 | if ''; then echo TRUE; else echo FALSE; fi |
| 16 | ## stdout: FALSE |
| 17 | ## status: 0 |
| 18 | |
| 19 | #### If subshell true |
| 20 | if `true`; then echo TRUE; else echo FALSE; fi |
| 21 | ## stdout: TRUE |
| 22 | ## status: 0 |
| 23 | |
| 24 | #### If subshell true WITH OUTPUT is different |
| 25 | if `sh -c 'echo X; true'`; then echo TRUE; else echo FALSE; fi |
| 26 | ## stdout: FALSE |
| 27 | ## status: 0 |
| 28 | |
| 29 | #### If subshell true WITH ARGUMENT |
| 30 | if `true` X; then echo TRUE; else echo FALSE; fi |
| 31 | ## stdout: FALSE |
| 32 | ## status: 0 |
| 33 | |
| 34 | #### If subshell false -- exit code is propagated in a weird way (strict-argv prevents) |
| 35 | if `false`; then echo TRUE; else echo FALSE; fi |
| 36 | ## stdout: FALSE |
| 37 | ## status: 0 |